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Sagot :
Answer:
[tex]9\frac{1}{3}[/tex] regular donut and [tex]14 \frac{2}{3}[/tex] fancy donut
Step-by-step explanation:
if you set up r as number of regular donut and f as number of fancy donut, you can set 2 equations
equation 1: r + f = 24
where 24 is the number of donut should add up or 2 dozens
equation 2: 1r + 1.3f = 28.80
where left sides reflect the prize of each type of donut equal to 28.80
solving by substracting equation 2 to equation 1 you'll get 0.3f = 4.40, so f = [tex]14 \frac{2}{3}[/tex] fancy donut
r= 24-f so r = [tex]9\frac{1}{3}[/tex] regular donut
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