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Sagot :
The probability that she chooses 2 pieces of fruit that are not bananas is 7/12
How to determine the probability?
The distribution of fruits is given as:
Pear = 3
Orange = 4
Banana = 2
This means that:
Not banana = 7
Banana = 2
Total = 9
The probability of not picking a banana in the first selection is:
P(1) = 7/9
Now there are 8 fruits in total left, and 6 fruits that are not banana
The probability of not picking a banana in the second selection is:
P(2) = 6/8
The required probability is:
P = 7/9 * 6/8
Evaluate
P = 7/12
Hence, the probability that she chooses 2 pieces of fruit that are not bananas is 7/12
Read more about probability at:
https://brainly.com/question/251701
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