At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
The mechanical energy of the system is sum of the potential and kinetic
energy of the system.
Response:
- E1 increases, E2 decreases
Methods by which the the above response is obtained
Mechanical energy, M.E. in the block and spring system can be presented as follows;
M.E. = Energy in the spring + Kinetic energy of the blocks + Energy done on friction
- Mechanical energy of the block-spring system, E1
When the blocks are held at rest;
The mechanical energy in the block-spring system when the blocks are held at rest can be found as follows;
Energy in the spring = 0
Kinetic energy of the blocks = 0
Friction energy = 0
Therefore;
E1 for the block at rest = 0
E1 when the blocks come to rest again
Energy in the spring = [tex]\mathbf{\frac{1}{2} \cdot k \cdot x^2}[/tex] > 0
Kinetic energy = 0
Energy of friction = 0
Therefore;
The mechanical energy of the block-spring system, E1, increases
- The mechanical energy of the block-spring-Earth system, E2
When the blocks are held
Energy in the spring = 0
Energy done due to friction = 0
Potential energy of Block B = m·g·h
Kinetic energy of the blocks = 0
When the blocks come to rest again, we have;
Energy in the spring = [tex]\frac{1}{2} \cdot k \cdot x^2[/tex]
Energy received due to friction = 0
Potential energy of Block B = m·g·(h - y)
Where;
[tex]m \cdot g \cdot h = \mathbf{m \cdot g \cdot (h - y) + \frac{1}{2} \cdot k \cdot x^2 + Energy \ loss \ due \ to \ friction}[/tex]
Which gives;
[tex]m\cdot g \cdot h > m \cdot g \cdot (h - y) + \frac{1}{2} \cdot k \cdot x^2[/tex]
The energy in the spring-block-Earth system, E2, when initially held is more than the the energy when the blocks com to rest again.
Therefore, E2 decreases
The correct option is therefore;
- E1 increases, E2 decreases
The possible question options obtained from a similar question posted online are;
- E1 increases, E2 decreases
- E1 decreases, E2 increases
- E1 is constant, and E2 decrease
- E1 and E2 remain constant
Learn more about mechanical energy here;
https://brainly.com/question/5398294
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.
