Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
This problem is describing a sample of krypton which undergoes a change in its temperature and pressure by holding its amount constant. As the initial pressure of the gas was 20.0 atm and the temperature is halved, one can use the Gay-Lussac's formula to prove that the result is 10 atm according to the following:
Gay-Lussac's law:
In chemistry, gas laws are used to relate changes in pressure, volume, moles and temperatures in a gas or gas mixture in agreement with the concept of ideal gases.
In this case, since the temperature and pressure are said to change, whereas the moles and volume of the gas remain unchanged, we can recall the Gay-Lussac's law as a directly proportional relationship between pressure and temperature:
[tex]\frac{P_2}{T_2} =\frac{P_1}{T_1}[/tex]
Thus, we can solve for P2 and subsequently plug in the initial pressure and the T2/T1 ratio (halved) to get:
[tex]P_2=\frac{P_1T_2}{T_1} \\\\P_2=20atm*0.5\\\\P_2=10atm[/tex]
Learn more about gas laws: https://brainly.com/question/1190311
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.