Looking for trustworthy answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
This problem is describing a sample of krypton which undergoes a change in its temperature and pressure by holding its amount constant. As the initial pressure of the gas was 20.0 atm and the temperature is halved, one can use the Gay-Lussac's formula to prove that the result is 10 atm according to the following:
Gay-Lussac's law:
In chemistry, gas laws are used to relate changes in pressure, volume, moles and temperatures in a gas or gas mixture in agreement with the concept of ideal gases.
In this case, since the temperature and pressure are said to change, whereas the moles and volume of the gas remain unchanged, we can recall the Gay-Lussac's law as a directly proportional relationship between pressure and temperature:
[tex]\frac{P_2}{T_2} =\frac{P_1}{T_1}[/tex]
Thus, we can solve for P2 and subsequently plug in the initial pressure and the T2/T1 ratio (halved) to get:
[tex]P_2=\frac{P_1T_2}{T_1} \\\\P_2=20atm*0.5\\\\P_2=10atm[/tex]
Learn more about gas laws: https://brainly.com/question/1190311
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.