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i was given the answer but i dont know how to solve please help & explain

I Was Given The Answer But I Dont Know How To Solve Please Help Amp Explain class=

Sagot :

Answer:

  x⁴ -3x³ -x² -27x -90

Step-by-step explanation:

We generally study polynomials that have real (and rational) coefficients. One of the features of such polynomials is that irrational and/or complex roots come in conjugate pairs. That means the root -3i is always accompanied by the root +3i if the polynomial has rational coefficients.

For any polynomial, if q is a zero, then (x -q) is a factor.

Knowing that, you know the minimum polynomial with these roots will have factors ...

  (x -(-2)), (x -5), (x -(-3i)), and (x -3i)

The last two of these are recognizable as factors of the difference of squares:

  a² -b² = (a -b)(a +b)

  (x -3i)(x +3i) = x² -(3i)² = x² -(-9) = x² +9

Now, you know the factored polynomial is ...

  y = (x +2)(x -5)(x² +9)

You can use the distributive property repeatedly to expand this to standard form.

  y = (x² -3x -10)(x² +9) = x²(x² -3x -10) +9(x² -3x -10)

  y = x⁴ -3x³ -10x² +9x² -27x -90

  y = x⁴ -3x³ -x² -27x -90

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Additional comment

For the purpose here, an irrational root will be of the form (for rational a, b, c) ...

  a +b√c . . . . where c is not a perfect square

and a complex root will be of the form ...

  a +bi

The conjugate of either of these forms is obtained by changing the sign:

  a -b√c  or  a -bi

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You may notice that the form a±b√c will include the form a±bi when c is negative. So, the conjugate pairs we're talking about are this form with either of c < 0 or c not a perfect square, or both.