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Calculate the mass of hydrogen in 57. 010 grams of ammonium hydrogen phosphate.

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Eduard22sly

The mass of hydrogen in 57.010 g ammonium hydrogen phosphate, (NH₄)H₂PO₄ is 2.97 g  

Determination of mass of 1 mole of (NH₄)H₂PO₄

1 mole of (NH₄)H₂PO₄ = 14 + (4×1) + (2×1) + 31 + (16×4) = 115 g

Determination of the mass of H in 1 mole of (NH₄)H₂PO₄

Mass of H = 6H = 6 × 1 = 6 g

Determination of the mass of H in 57.010 g of (NH₄)H₂PO₄

115 g of (NH₄)H₂PO₄ contains 6 g of H.

Therefore,

57.010 g of (NH₄)H₂PO₄ will contain = (57.010 × 6) / 115 = 2.97 g of H

Thus, 2.97 g of Hydrogen, H is present in 57.010 g of (NH₄)H₂PO₄

Learn more about mass composition:

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