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[Maximum mark: 6]
In the expansion of px^2(5+px)^8 , the coefficient of the term in x^6 is 3402. Find the value of p.

help and explain please.




Maximum Mark 6 In The Expansion Of Px25px8 The Coefficient Of The Term In X6 Is 3402 Find The Value Of P Help And Explain Please class=

Sagot :

The value of p is 0.6

What is a binomial expression?

A binomial expression is an algebraic expression that contains only two terms.

Binomial expansions are used to expand exponents of two terms

The expression is given as:

[tex]px^2(5 + px)^8[/tex]

When the expression in bracket is expanded, one of its term is:

[tex]px^2(5 + px)^8 = px^2 (..........70 \times p^4 \times x^4...........)[/tex]

So, we have:

[tex]px^2(5 + px)^8 = px^2 (..........70 \times 5^4 \times (px)^4...........)[/tex]

[tex]px^2(5 + px)^8 = px^2 (..........70 \times 625 \times (px)^4...........)[/tex]

[tex]px^2(5 + px)^8 = px^2 (..........43750 (px)^4...........)[/tex]

[tex]px^2(5 + px)^8 = px^2 (..........43750 p^4x^4...........)[/tex]

Expand the bracket, to get the coefficient of x^6

[tex]px^2(5 + px)^8 = px^2 (..........43750 p^5x^6...........)[/tex]

The coefficient equals 3402.

So, we have:

[tex]43750p^5 = 3402[/tex]

Divide both sides by 43750

[tex]p^5 = 0.07776[/tex]

Take the 5th root of both sides

[tex]p = 0.6[/tex]

Hence, the value of p is 0.6

Read more about binomial expansions at:

https://brainly.com/question/13602562