Answer:
y=[tex]\frac{3}{8}x - \frac{3}{2}[/tex]
Step-by-step explanation:
Hi there!
We are given the equation 3x-8y=12, and we want to convert it from standard form into slope intercept form
- Standard form is ax+by=c, which is the form that the equation is in right now
- Slope-intercept form is y=mx+b, where m is the slope and b is the y intercept, which is the form we want the equation to be in
In slope-intercept form, y is isolated on one side, while everything else is on the other side.
In other words, we'll need to solve for y in order to convert from standard to slope-intercept form
Start by subtracting 3x from both sides
3x-8y=12
-3x -3x
________
-8y = -3x + 12
Like any equation, we want just the value of y by itself. So divide both sides by -8
y=[tex]\frac{-3}{-8}x + \frac{12}{-8}[/tex]
You may simplify the equation; [tex]\frac{-3}{-8}[/tex] is the same as just [tex]\frac{3}{8}[/tex].
You may divide by 4 on both the numerator and the denominator of [tex]\frac{12}{-8}[/tex], to get [tex]\frac{3}{-2}[/tex] and then bring the minus sign up in front ([tex]-\frac{3}{2}[/tex])
The equation will now be
y=[tex]\frac{3}{8}x + -\frac{3}{2}[/tex], or y = [tex]\frac{3}{8}x - \frac{3}{2}[/tex]
Hope this helps!
