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A football is kicked at 37.0o to the horizontal at 20.0 m/s from the player’s hand at 1.00 m from the ground. How far did the football travel before hitting the ground​

Sagot :

The distance traveled by the ball before hitting the ground is 7.2 m.

The given parameters:

  • Angle of projection, θ = 37⁰
  • Horizontal velocity, V = 20 m/s
  • Height above the ground, h = 1 m

Vertical motion of a projectile;

  • The vertical motion of a projectile is affected by gravity.

The time of motion of the ball is calculated as follows;

[tex]h= v_y_i t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2 \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 1}{9.8} }\\\\t =0.45 \ s[/tex]

The horizontal distance traveled by the ball before hitting the ground is calculated as follows;

[tex]X = v_x \times t\\\\X = vcos\theta \times t\\\\X = 20 \times cos(37) \times 0.45\\\\X = 7.2 \ m[/tex]

Thus, the distance traveled by the ball before hitting the ground is 7.2 m.

Learn more about horizontal distance here: https://brainly.com/question/24784992

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