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A car accelerates uniformly from rest and
reaches a speed of 24.8 m/s in 12.2 s. The
diameter of a tire is 49.9 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping


Sagot :

Explanation:

Tire circumference = pi d

3.142*49.9 = 156.79 cm

156.79 / 100 = 1.57m

For one revolution 1.57 m moved

24.8 * 12.2 = 302.56 m total distance traveled

302.56/1.57 = 192.7 revolutions