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A block of wood weighing 55.0 N is sliding on a surface. If a force of 37.1 N is necessary to keep it sliding at a constant velocity, what is the coefficient of kinetic friction of the wood on the surface?

Sagot :

asuwafohjames

The coefficient of kinetic friction of the wood on the surface is 0.675.

Kinetic friction:

This is the force that acts between two moving surfaces. The magnitude of the force depends on the coefficient of kinetic friction.

To calculate the coefficient of kinetic friction of the wood on the surface, we use the formula below.

⇒  Formula:

  • F = Wμ................ Equation 1

⇒ Where:

  • F = Force needed to keep the block sliding at a constant velocity.
  • W = Weight of the wood
  • μ = coefficient of kinetic friction of the wood on the surface

⇒ Make μ the subject of the equation

  • μ = F/W............... Equation 2

From the question,

⇒ Given:

  • F = 37.1 N
  • W = 55.0 N

⇒ Substitute these values into equation 2

  • μ = 37.1/55
  • μ = 0.675.

Hence,  the coefficient of kinetic friction of the wood on the surface is 0.675.

Learn more about friction here: https://brainly.com/question/24338873

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