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Find the equation of the line using the point-slope formula. Write the final equation using slope-intercept form. (1,2) with a slope of -3/4

So because I am horrible at Algebra I would kindly like to ask somebody to assist me if they are willing please and thank you.

Sagot :

theleangreenbean

Answer:

[tex]y-2=\displaystyle -\frac{3}{4}(x-1)[/tex]

OR

[tex]y=\displaystyle -\frac{3}{4}x+\frac{11}{4}[/tex]

Step-by-step explanation:

Hi there!

Point-slope form: [tex]y-y_1=m(x-x_1)[/tex] where m is the slope of the line and [tex](x_1,y_1)[/tex] is a given point

Given that the slope is -3/4, we can plug it into [tex]y-y_1=m(x-x_1)[/tex] as m:

[tex]y-y_1=\displaystyle -\frac{3}{4}(x-x_1)[/tex]

We can also plug in the given point (1,2):

[tex]y-2=\displaystyle -\frac{3}{4}(x-1)[/tex]

Slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis)

To write the equation in slope-intercept form, isolate y:

[tex]y-2=\displaystyle -\frac{3}{4}(x-1)\\\\y=\displaystyle -\frac{3}{4}(x-1)+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{3}{4}+2\\\\y=\displaystyle -\frac{3}{4}x+\frac{11}{4}[/tex]

I hope this helps!

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