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Answered

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8.
The San Antonio Spurs played 112 games
during the 2006 basketball season. If they lost
20, about what percent of their games did they
lose?

Sagot :

anishkonduri

Since the total amount of games played is 112, we have to divide 20 (how many games they lost during that season) by 112 and multiply that by 100 to find the percent of the games that they lost.

Work:

20/112 is approximately 0.1786 in decimal form, so to convert that into a percentage, we multiply that by 100.

0.1786 x 100 = 17.86

Answer:

The spurs lost about 17.86% of their games during the 2006 basketball season.

Hopefully that helps!

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