Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
The amount of Polonium-120 present after 1 year is 7.36 grams.
Half-life:
This is the time taken for half the sample of a radioactive material to decay.
To calculate the amount of Polonium-120 present after 1 year, we use the formula below.
Formula:
- R' = R/([tex]2^{a/n} [/tex])................ Equation 1
Where:
- R = Amount of Polonium-120 present now
- R' = Amount of Polonium-120 present after 1 year
- a = Total time
- n = Half-life
From the question,
Given:
- R = 45 grams
- a = 1 year = 365 days
- n = 40 days.
Substitute these values into equation 1
- R' = 45/(2³⁶⁵/¹⁴⁰)
- R' = 45/6.11
- R' = 7.36 grams.
Hence, The amount of Polonium-120 present after 1 year is 7.36 grams
Learn more about half-life here: https://brainly.com/question/11152793
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.