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Sagot :
The amount of Polonium-120 present after 1 year is 7.36 grams.
Half-life:
This is the time taken for half the sample of a radioactive material to decay.
To calculate the amount of Polonium-120 present after 1 year, we use the formula below.
Formula:
- R' = R/([tex]2^{a/n} [/tex])................ Equation 1
Where:
- R = Amount of Polonium-120 present now
- R' = Amount of Polonium-120 present after 1 year
- a = Total time
- n = Half-life
From the question,
Given:
- R = 45 grams
- a = 1 year = 365 days
- n = 40 days.
Substitute these values into equation 1
- R' = 45/(2³⁶⁵/¹⁴⁰)
- R' = 45/6.11
- R' = 7.36 grams.
Hence, The amount of Polonium-120 present after 1 year is 7.36 grams
Learn more about half-life here: https://brainly.com/question/11152793
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