Answer:
3x + 2
{8, 11, 14}
Step-by-step explanation:
given that a function has a domain {2,3,4}, this means that the x-values of the function can only be the 2, 3 and 4.
knowing this, the first pulldown box gives a choice of two different functions
choice A : f(x) = 3x + 2
choice B : f(x) = x + 1
Simply substituting the domain (i.e the values 2, 3 and 4) into these functions determine the range as follows:
For choice A:
f(x) = 3x + 2, for domain {2,3,4)
f(2) = 3(2) + 2 = 8
f(3) = 3(3) + 2 = 11
f(4) = 3(4) + 2 = 14
Right away we can see that the range is {8, 11, 14} which is one of the choices in the second pull down box. We suspect that this is the correct answer, but let's have a look at Choice B for a sanity check.
For Choice B:
f(x) = x + 1, for domain {2,3,4)
f(2) = 2 + 1 = 3
f(3) = 3 + 1 = 4
f(4) = 4 + 1 = 5
We can see that choice B gives a range of {3,4,5}, which is neither of the choices in the pull down box. Hence we can surmise that this is not the answer and choice A is the correct answer
