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An 18, 000 kg semi containing Lex Luthor in the process of stealing forty cakes is moving with a speed of 15 m/s . If Superman is to stop the van in 0.5 seconds, what force must he exert on the van?

Sagot :

Answer:

540000 Newtons

Explanation:

F = m*a

Acceleration = [tex]\frac{Change in Velocity}{time}[/tex]

The van is originally travelling at 15m/s, if superman stops the car, then it ends with a velocity of 0m/s, and he does this in 0.5 seconds. Therefore the acceleration of superman stopping the van is  [tex]\frac{0m/s - 15m/s}{0.5s} = -30m/s^2[/tex] (Final velocity - initial velocity) / Time

Mass of van is 18,000 kg.

Force = 18,000 kg * -30m/s^2

Note that force is scalar, so it is always positive regardless of the sign of acceleration.

540000 N

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