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Sagot :
(total mark/number of subjects)Ă—100=63
(total mark+20+2)/(number of subjects)Ă—100=65
(total mark+22)/number of subjects=0.65
let n be the total number of subjects
((0.63 of 100n)+22)Ă·(100n)=0.65
because he obtained only 63 percent from sum of all marks.(marks counted from 100)
(0.63Ă—100n+22)Ă·(100n)=0.65
0.63+(22Ă·100n)=0.65
0.22Ă·n=0.65-0.63
0.22Ă·n=0.02
n=0.22/0.02
n=11
there were 11 subjects
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