Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
[tex]4 {a}^{3} - a {}^{2} = 2 {a }^{2} \\ a {}^{2} (4a - 1) = 2 \times {a}^{2} \\ 4a - 1 = 2 \\ 4a = 2 + 1 \\ 4a = 3 \\ a = \frac{3}{4} [/tex]
Answer:
the three solutions are 0, 0 and 3/4.
Step-by-step explanation:
Solve 4a^3-a^2=2a^2.
Rewrite this so that all terms are on the left with the exception of 0 on the right: 4a^3 - a^2 - 2a^2 = 0
Combining like terms, we get
4a^3 - 3a^2 = 0
Recognize that these two terms have the common factor a^2. Thus, this 4a^3-a^2=2a^2 becomes (a^2)(4a - 3) = 0, and so the three solutions are 0, 0 and 3/4.
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.