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solve the equation: 4a^3-a^2=2a^2

Sagot :

nileshyadav85907

[tex]4 {a}^{3} - a {}^{2} = 2 {a }^{2} \\ a {}^{2} (4a - 1) = 2 \times {a}^{2} \\ 4a - 1 = 2 \\ 4a = 2 + 1 \\ 4a = 3 \\ a = \frac{3}{4} [/tex]

altavistard

Answer:

the three solutions are 0, 0 and 3/4.

Step-by-step explanation:

Solve 4a^3-a^2=2a^2.  

Rewrite this so that all terms are on the left with the exception of 0 on the right:  4a^3 - a^2 - 2a^2 = 0

Combining like terms, we get

          4a^3 - 3a^2 = 0

Recognize that these two terms have the common factor a^2.  Thus, this 4a^3-a^2=2a^2 becomes (a^2)(4a - 3) = 0, and so the three solutions are 0, 0 and 3/4.

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