Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

the length of a rectangle is twice its width. find the area if its perimiter is 7 1/3 cm

Sagot :

Hmmm try asking someone for help

Answer:

Area = 2.99 cm2

Step-by-step explanation:

[tex]P=2l+2w[/tex]

If:

[tex]l=2w\\P=7\frac{1}{3} cm=\frac{22}{3} cm[/tex]

Then

[tex]\frac{22}{3} =2(2w)+2w[/tex]

[tex]\frac{22}{3} =6w[/tex]

[tex]\frac{22}{18} =w[/tex]

[tex]l=2w=2(\frac{22}{18} )=\frac{44}{18}[/tex]

lenght simplified=22/9

width simplified = 11/9

Area.

[tex]A=lw=(\frac{22}{9} )(\frac{11}{9} )=(\frac{242}{81} )=2.99cm^{2}[/tex]

Hope this helps