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Three numbers form a geometric progression. If the second term is increased by 2, the progression will become arithmetic and if, after this, the last term is increased by 9, then the progression will again become geometric. Find these three numbers I found the first answer (4,8,16) what is the second answer? HELP

Sagot :

The geometric and arithmetic progression are a number series such that

each term is given by adding or multiplying the previous term by a constant.

Responses:

The possible three numbers are;

  • 4, 8, 16
  • [tex]\displaystyle \frac{4}{25} , \ -\frac{16}{25}, \ \frac{64}{25}[/tex]

Methods by which the above responses are obtained:

Let the three numbers be a, a·r, and a·r², we have;

Given;

G.P. = a, a·r, a·r²

A.P. = a, a·r + 2, a·r²

G.P. = a, a·r + 2, a·r² + 9

Solution:

(a·r + 2) - a = a·r² - (a·r + 2) by definition of an AP

a·r + 2 - a = a·r² - (a·r + 2)

(r² - 2·r + 1)·a - 4 = 0

G.P = a, a·r + 2, a·r² + 9

[tex]\displaystyle \frac{a \cdot r + 2}{a} = \frac{a \cdot r^2 + 9}{a \cdot r + 2}[/tex]

(a·r + 2)² = a·(a·r² + 9)

r²·a² + 4·r·a + 4 = r²·a² + 9·a

4·r·a + 4 = 9·a

4 = 9·a - 4·r·a = a·(9 - 4·r)

[tex]\displaystyle a = \mathbf{ \frac{4}{9 - 4 \cdot r}}[/tex]

[tex]\displaystyle \left(r^2 - 2 \cdot r + 1 \right) \times \frac{4}{9 - 4 \cdot r} - 4 = 0[/tex]

Therefore;

[tex]\displaystyle \left(r^2 - 2 \cdot r + 1 \right) \times \frac{4}{9 - 4 \cdot r} \times (9 - 4 \cdot r) - 4 \times (9 - 4 \cdot r)= 0[/tex]

4·r² + 8·r - 32 = 0

Which gives;

4·r² + 8·r - 32 = 4·(r - 2)·(r + 4) = 0

r = 2 or r = -4

[tex]\displaystyle a = \frac{4}{9 - 4 \times 2} = \mathbf{ 4}[/tex] or [tex]\displaystyle a = \frac{4}{9 - 4 \times (-4)} = \frac{4}{25}[/tex]

The first three numbers are;

4, 4 × 2, 4 × 2², which gives;

  • 4, 8, 16

[tex]\displaystyle When \ a = \frac{4}{25}, and \ r = -4, we \ have;[/tex]

[tex]\displaystyle \frac{4}{25}, \ \frac{4}{25} \times (-4), \ \frac{4}{25} \times (-4)^2[/tex]

Which gives;

[tex]\displaystyle \frac{4}{25} , \ -\frac{16}{25} , \ \frac{64}{25}[/tex]

[tex]\displaystyle The \ second \ three \ numbers \ are; \underline{\frac{4}{25}, \ -\frac{16}{25} , \ \frac{64}{25}}[/tex]

Learn more about geometric and arithmetic progression here:

https://brainly.com/question/1800090