Answered

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Given these equations:
x+y=9.0
0.50x+0.20y=3.15
Find the values of x and y.

Sagot :

naǫ
[tex]x+y=9 \\ 0.5x+0.2y=3.15 \ \ \ |\times (-2) \\ \\ x+y=9 \\ \underline{-x-0.4y=-6.3} \\ y-0.4y=9-6.3 \\ 0.6y=2.7 \\ y=\frac{2.7}{0.6} \\ y=\frac{27}{6} \\ y=\frac{24}{6}+\frac{3}{6} \\ y=4\frac{1}{2} \\ \\ x+y=9 \\ x+4 \frac{1}{2}=9 \\ x=9-4\frac{1}{2} \\ x=4\frac{1}{2} \\ \\ (x,y)=(4\frac{1}{2},4\frac{1}{2}) [/tex]
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