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Sagot :
I believe it is 2 because if you have 2 of 3/8's you would have 6/8 and you can't really add another 3/8 to that to get one because you will have 1 and 1/8
[tex]1:\frac{3}{8}=1\times\frac{8}{3}=\frac{8}{3}=\frac{6+2}{3}=\frac{6}{3}+\frac{2}{3}=\boxed{2\frac{2}{3}-times}\\\\conclusion:\\\\\frac{3}{8}\ are\ in\ 1:\boxed{2\ times} [/tex]
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