Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

A football is kicked straight up in the air , it hits the ground 5.6 s later. What was the greatest height kicked reached by the ball? Assume it was kicked at ground level.

Sagot :

arenite
We'll just consider the down trip, from when it was at its highest point to when it hits the ground.  Initial velocity is 0 m/s, acceleration is 9.81 m/s^2 (gravity), and time is 5.6s.

One of the kinematic equations is d = (Vi)(t) + 0.5(a)(t^2).
Plugging it in gives us d = 0 + (0.5)(9.81)(5.6^2) = 153.8208 m.

Hope this helped!
Edufirst

Answer: 38.5 m

Explanation:

1) Flight time = 5.6 s (given)

2) Ascending time = fligth time / 2 = 5.6s / 2 = 2.8 s

3) Vf = Vo - gt

Hmax ⇒ Vf = 0

⇒ 0 = Vo - gt ⇒ Vo = gt = 9.81m/s² (2.8s) = 27.5 m/s

4) H = Vot - gt² / 2

⇒ H = 27.5m/s(2.8s) - 9.81m/s² (2.8s)² / 2 = 77m - 38.5m = 38.5m

Answer: 38.5m

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.