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Sagot :
[tex]A+B=76\to A=76-B\\\\A-B=38\to A=38+B\\\\\Downarrow\\\\38+B=76-B\\B+B=76-38\\2B=38\ \ \ /:2\\B=19\\\\\Downarrow\\\\A=76-19=57[/tex]
[tex]\Downarrow\\\\A:B=57:19=3[/tex]
[tex]\Downarrow\\\\A:B=57:19=3[/tex]
For this case we have the following system of equations:
[tex] A + B = 76
A-B = 38
[/tex]
Solving the system of equations we have:
1) We subtract equation 1 with equation 2:
[tex] 2B = 76 - 38
2B = 38
[/tex]
2) We clear the value of B:
[tex] B = \frac{38}{2}
B = 19
[/tex]
3) We substitute The value of B in equation 2 and obtain the value of A:
[tex] A-B = 38
A-19 = 38
A = 38 + 19
A = 57
[/tex]
Then, the value of the division of both numbers is:
[tex] \frac{A}{B}= \frac{57}{19} = 3
[/tex]
Answer:
[tex] \frac{A}{B} = 3 [/tex]
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