Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
[tex]A+B=76\to A=76-B\\\\A-B=38\to A=38+B\\\\\Downarrow\\\\38+B=76-B\\B+B=76-38\\2B=38\ \ \ /:2\\B=19\\\\\Downarrow\\\\A=76-19=57[/tex]
[tex]\Downarrow\\\\A:B=57:19=3[/tex]
[tex]\Downarrow\\\\A:B=57:19=3[/tex]
For this case we have the following system of equations:
[tex] A + B = 76
A-B = 38
[/tex]
Solving the system of equations we have:
1) We subtract equation 1 with equation 2:
[tex] 2B = 76 - 38
2B = 38
[/tex]
2) We clear the value of B:
[tex] B = \frac{38}{2}
B = 19
[/tex]
3) We substitute The value of B in equation 2 and obtain the value of A:
[tex] A-B = 38
A-19 = 38
A = 38 + 19
A = 57
[/tex]
Then, the value of the division of both numbers is:
[tex] \frac{A}{B}= \frac{57}{19} = 3
[/tex]
Answer:
[tex] \frac{A}{B} = 3 [/tex]
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.