Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

A 2.650 grams sample of gas occupies a volume of 428cm^3 at a pressure of 99.06 kPa and 24.3˚C. Analysis of this compound reveals a composition of 15.5% C, 23.0% Cl and61.5% F by mass. Determine the true, molecular, formula.

Sagot :

Eduard22sly

The true molecular formula of the compound is C₂ClF₅

Determination of the mole of the compound

  • Volume (V) = 428 cm³ = 428 / 1000 = 0.428 L
  • Pressure (P) = 99.06 KPa = 99.06 / 101.325 = 0.978 atm
  • Temperature (T) = 24.3˚C = 24.3 + 273 = 297.3 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Number of mole (n) =?

The number of mole can be obtained as by using the ideal gas equation as illustrated below:

n = PV / RT

n = (0.978 × 0.428) / (0.0821 × 297.3)

n = 0.017 mole

How to determine the molar mass

  • Mole = 0.017 mole
  • Mass = 2.650 g
  • Molar mass =?

Molar mass = mass / mole

Molar mass = 2.650 / 0.017

Molar mass = 155.88 g/mol

How to determine the empirical formula

  • Carbon (C) = 15.5%
  • Chlorine (Cl) = 23%
  • Fluorine (F) = 61.5%
  • Empirical formula =?

Divide by their molar mass

C = 15.5 / 12 = 1.292

Cl = 23 / 35.5 = 0.648

F = 61.5 / 19 = 3.237

Divide by the smallest

C = 1.292 / 0.648 = 2

Cl = 0.648 / 0.648 = 1

F = 3.237 / 0.648 = 5

Thus, the empirical formula of the compound is C₂ClF₅

How to determine the molecular formula

  • Molar mass of compound = 155.88 g/mol
  • Empirical formula = C₂ClF₅
  • Molecular formula =?

Molecular formula = empirical × n = molar mass

[C₂ClF₅]ₙ = 118.084

[(12×2) + 35.5 + (19×5)]ₙ = 155.88

154.5n = 155.88

Divide both side by 154.5

n = 155.88 / 154.5

n = 1

Molecular formula = [C₂ClF₅]ₙ

Molecular formula = [C₂ClF₅]1

Molecular formula = C₂ClF₅

Learn more about empirical and molecular formula:

https://brainly.com/question/24297883

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.