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Which inequalities would have an open circle when graphed? Check all that apply. T Less-than-or-equal-to 25 -2. 5 Less-than-or-equal-to m x > 5. 4 One-half less-than x x > 0.

Sagot :

The inequalities would have an open circle when graphed are as follows;

The inequality shows that it does not contain boundary point 5.

        [tex]\rm x>5.4[/tex]

The inequality shows that it does not contain the boundary point 1/2.

        [tex]\rm \dfrac{1}{2}>x[/tex]

The inequality shows that it does not contain the boundary point 0.

        [tex]\rm x>0[/tex]

What is a circle?

A round plane figure whose boundary (the circumference) consists of points equidistant from a fixed point (the center):

The graph will have an open circle only if it has the symbol < or > because it indicates that the boundary is not included.

  • The inequality shows that it does not contain boundary point 5.

        [tex]\rm x>5.4[/tex]

  • The inequality shows that it does not contain the boundary point 1/2.

        [tex]\rm \dfrac{1}{2}>x[/tex]

  • The inequality shows that it does not contain the boundary point 0.

        [tex]\rm x>0[/tex]

To know more about circles click the link given below.

https://brainly.com/question/11833983

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