samilovesyou678
Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

can someone help please? this is trigonometry

Can Someone Help Please This Is Trigonometry class=

Sagot :

denishsaud1205

Answer:

Solution,

hypotenuse (h)=x

perpendicular(p)=9

base(b)=53°

Using pythagoras theorem,

[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]

[tex] {x}^{2} = {9}^{2} + {53}^{2} [/tex]

[tex] {x}^{2} = 81 + 2809[/tex]

[tex] {x}^{2} = 2890[/tex]

[tex]x = \sqrt{2890} [/tex]

[tex]x = 53.75[/tex]

hope it helps you

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.