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I need help plzzzzz on thisisisjdsj math problem

I Need Help Plzzzzz On Thisisisjdsj Math Problem class=

Sagot :

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Here's the solution ~

Let's consider two points (-2 , 0) and (0 , 2) on the line to find the slope (m) :

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{y_2 - y_1}{x_2 - x _1} [/tex]

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{2 - 0}{0 - ( - 2)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{2}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: m = 1[/tex]

And, now let's observe the graph ; the distance of origin (sign included) from the point where the line cuts y - axis will be the y - intercept (c) .

That is : 2 - 0 = 2 units

Next step :

As we know any line can be expressed through slope intercept form ;

[tex]\qquad \sf  \dashrightarrow \: y = mx + c[/tex]

Here, m = slope and c = y - intercept [ already got the values ]

Now, use the values to find the equation ;

[tex]\qquad \sf  \dashrightarrow \: y = (1 \times x) + 2[/tex]

[tex]\qquad \sf  \dashrightarrow \: y = x + 2[/tex]

Therefore the required equation is ~

[tex] \large \qquad \qquad \sf \boxed{\boxed{ \sf y = x + 2}}[/tex]

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