rayangadalla
Answered

At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

I need help plzzzzz on thisisisjdsj math problem

I Need Help Plzzzzz On Thisisisjdsj Math Problem class=

Sagot :

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Here's the solution ~

Let's consider two points (-2 , 0) and (0 , 2) on the line to find the slope (m) :

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{y_2 - y_1}{x_2 - x _1} [/tex]

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{2 - 0}{0 - ( - 2)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{2}{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \: m = 1[/tex]

And, now let's observe the graph ; the distance of origin (sign included) from the point where the line cuts y - axis will be the y - intercept (c) .

That is : 2 - 0 = 2 units

Next step :

As we know any line can be expressed through slope intercept form ;

[tex]\qquad \sf  \dashrightarrow \: y = mx + c[/tex]

Here, m = slope and c = y - intercept [ already got the values ]

Now, use the values to find the equation ;

[tex]\qquad \sf  \dashrightarrow \: y = (1 \times x) + 2[/tex]

[tex]\qquad \sf  \dashrightarrow \: y = x + 2[/tex]

Therefore the required equation is ~

[tex] \large \qquad \qquad \sf \boxed{\boxed{ \sf y = x + 2}}[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.