sanchezachristie
Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

sorry for the weird marks but please help!!​

Sorry For The Weird Marks But Please Help class=

Sagot :

WeatherForecast

Answer:

C. 8 is the correct answer.

Step-by-step explanation:

Let <DAB be x°

Now,

taking x as reference angle in triangle ADB,

cosx = b/h

or, cosx = 4/AB

Now,

again taking x as reference angle in triangle ACB,

cosx = b/h

or, cosx = AB/20

Now,

cosx = AB/20 = 4/AB

or, AB/20 = 4/AB

or, AB² = 80

Now,

Using pythagoras theorem in triangle ABD,

h² = p² + b²

or, AB² = BD² + AD²

or, 80 = BD² + 4²

or, 80 - 16 = BD²

so, BD² = 64

so, BD = 8

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.