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A person is running at an initial velocity of 3.7 m/s. If the person is accelerating at 2 m/s2, what is their final velocity after 3 seconds?

Sagot :

Hi1315

Answer:

9.7 ms⁻¹

Explanation:

The formula to find the acceleration is :

[tex]Acceleration=\frac{Final \:Velocity-Initial\:Velocity}{Time}[/tex]

According to the question, we are asked to find the Final Velocity.

For that, let the Final Velocity be x.

[tex]Acceleration=\frac{Final \:Velocity-Initial\:Velocity}{Time}[/tex]

[tex]2m/s^{2} =\frac{x-3.7m/s}{3 s}\\[/tex]

[tex]2 =\frac{x-3.7}{3 }\\[/tex]

[tex]2*3=x-3.7[/tex]

[tex]6=x-3.7[/tex]

[tex]6+3.7=x[/tex]

[tex]9.7=x[/tex]

Therefore,

Final velocity = 9.7ms⁻¹

Hope this helps you :-)

Let me know if you have any other questions :-)

VirαtKσhli

Answer:

9.7m/s

Explanation:

[tex]\pink{\frak{Given}}\begin{cases} \textsf{ Initial velocity of a person is 3.7m/s .}\\\textsf{The acceleration of the person is 2m/s$^2$ .} \end{cases}[/tex]

And we need to find out the velocity of the person after 3 seconds . Here we can use the First equation of motion namely ,

[tex]\sf \longrightarrow v = u + at \\[/tex]

Where ,

  • v is the final velocity .
  • u is the initial velocity .
  • a is the acceleration .
  • t is the time taken .

Now substitute the respective values in the given equation ,

[tex]\sf \longrightarrow v = 3.7m/s + 2m/s^2*3s\\[/tex]

Simplify ,

[tex]\sf \longrightarrow v = 3.7m/s + 6m/s\\[/tex]

[tex]\sf \longrightarrow \boxed{\bf velocity_{After\ 3 \ s }= 9.7 m/s}\\[/tex]

Hence the velocity after 3 seconds is 9.7 m/s .

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