Answered

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Joaquin is at rest at the top of a hill on a skateboard. Four seconds later, he reaches the bottom of the hill at a final velocity of 20 m/s. What was his acceleration?

Sagot :

Explanation:

Given: Initial Velocity=0

Final Velocity= 20 m/s

Time= 4 s

Accleration: Unknowns

Use kinematic equation

[tex]v _{f} = v _{i} + at[/tex]

[tex]20 = 0 + at[/tex]

[tex] \frac{20m}{s} = a(4s)[/tex]

[tex]a = \frac{5m}{ {s}^{2} } [/tex]

so a = 5 m/s^2

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