Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

What is 6[cos(70°) i sin(70°)] ÷ 2[cos(5°) i sin(5°)]? 3[cos(75°) i sin(75°)] 4[cos(75°) i sin(75°)] 3[cos(65°) i sin(65°)] 4[cos(65°) i sin(65°)].

Sagot :

Step-by-step explanation:

If we have

[tex] \frac{r( \cos(x) + i \sin(x) }{s( \cos(v) + i \: sin(w)} = \frac{r}{s} ( \cos(x - v) + i \: sin(x - w)[/tex]

So first we know the modulus is 6 and 2 for the second one so we get

[tex] \frac{6}{2} = 3[/tex]

First degree is 70 , and second is 5 so our degree will be 65 in the second because

70-5=65

Our answer is

[tex]3( \cos(65) + i \: \sin(65) )[/tex]

kyliej7

Answer:c.

Step-by-step explanation:

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.