Answer:
5. [tex]\frac{2}{8}[/tex]
6. [tex]\frac{10}{12}[/tex]
7. [tex]\frac{11}{20}[/tex]
Step-by-step explanation:
5. [tex]\frac{1}{2} - (\frac{1}{8} +\frac{1}{8} )\\[/tex] = [tex]\frac{2}{8}[/tex]
Step 1: Solve for the fractions in the parentheses.
[tex]\frac{1}{8} +\frac{1}{8}[/tex]
This will be easy because they both have the same denominator.
= [tex]\frac{2}{8}[/tex]
Now we have:
[tex]\frac{1}{2} -\frac{2}{8}[/tex] =
Find the common denominator and change the numerator accordingly:
[tex]\frac{4}{8} -\frac{2}{8} = \frac{2}{8}[/tex]
6. [tex]\frac{3}{4} +(\frac{1}{4} -\frac{1}{6} )[/tex]
Step 1: Solve for the fractions inside the parentheses
Find the Common Denominator of both and change the numerators accordingly
[tex]\frac{1}{4} -\frac{1}{6} = \frac{3}{12} -\frac{2}{12}[/tex]
Then just subtract them
[tex]\frac{1}{12}[/tex]
Now we have:
[tex]\frac{3}{4} +\frac{1}{12}[/tex]
Find the common denominator:
[tex]\frac{9}{12} + \frac{1}{12}[/tex]
Then just add them
[tex]\frac{10}{12}[/tex]
7. [tex](\frac{1}{2} +\frac{3}{20} )-\frac{2}{20}[/tex]
Step 1: Solve the fractions in the parentheses
[tex]\frac{1}{2} +\frac{3}{20} =\frac{10}{20} +\frac{3}{20}[/tex]
Then solve
[tex]\frac{10}{20} +\frac{3}{20} =\frac{13}{20}[/tex]
Now we have
[tex]\frac{13}{20} -\frac{2}{20}[/tex]
Subtract
= [tex]\frac{11}{20}[/tex]
