malhefeiti696
Answered

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can anyone help me to solve the question

Can Anyone Help Me To Solve The Question class=

Sagot :

Answer:

x = 2[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² + 9² = 11²

x² + 81 = 121 ( subtract 81 from both sides )

x² = 40 ( take square root of both sides )

x = [tex]\sqrt{40}[/tex] = [tex]\sqrt{4(10)}[/tex] = [tex]\sqrt{4}[/tex] × [tex]\sqrt{10}[/tex] = 2[tex]\sqrt{10}[/tex] ≈ 6.32 ( to 2 dec. places )

Binay5524

Answer:

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View image Binay5524
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