Answer:
in the figure four quadrants each of radius 2 m are removed from a rectangle.
I have attached the required figure, assuming the sides of a rectangle based on given measurement of quadrants.
Let the sides of a rectangle be 2 m × 4 m.
The radius of quadrant is 2 m ( given )
From given, we have
Area of figure = Area of 4 quadrants - Area of rectangle .
= 4 × π/4 × r² - l × w
= 4 × π/4 × 2² - 2 × 4
= 3.14 × 4 - 8
= 12.4 - 8
= 4.4 m²
Therefore, the area of the figure is 4.4 m²
Perimeter of figure = Perimeter of 4 quadrants - Perimeter of rectangle
= 4 × [ 0.5πr + 2r ] - 2 ( l + w )
= 4 × [ 0.5 × 3.14 × 2 + 2 × 2 ] - 2 ( 4 + 2 )
= 4 × [ 3.14 + 4 ] - 2 (6)
= 28.56 - 12
= 16.56 m
the perimeter of the figure is 16.56 m