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Divide R4 625 amongst Andrew, Brendan, and Clair so that for every R4 that Andrew gets, Brendan gets R3 and for every R4 that Brendan gets, Clair gets R3.

Sagot :

The amount each of Andrew, Brendan, and Clair gets is given by

representation as fractions.

Response:

  • Andrew gets R2,000, Brendan gets R1,500, and Clair gets R1,125

Which method can be used to find the amount each person gets?

Given:

The amount to be divided = R4 625

Every R4 Andrew gets, Brendan gets R3

Every R4 Brendan gets Clair gets R3

The amount each person gets from the R4625 to divided is found as

follows;

Let x represent the amount Andrew gets, we have;

Amount Brendan gets = [tex]\frac{3}{4}[/tex]·x

Amount Clair gets = [tex]\frac{3}{4}[/tex]·[tex]\frac{3}{4}[/tex]·x = [tex]\mathbf{\frac{9}{16}}[/tex]·x

Which gives;

[tex]4625 = x + \dfrac{3}{4} \cdot x + \dfrac{9}{16} \cdot x= \mathbf{ \dfrac{37 \cdot x}{16}}[/tex]

Therefore;

[tex]x = \mathbf{4625 \times \dfrac{16}{37}} = 2000[/tex]

x = 2000

  • The amount Andrew gets, x = R2,000
  • Amount Brendan gets =  [tex]\frac{3}{4}[/tex]·x = [tex]\frac{3}{4}[/tex] × R2000 = R1,500
  • The amount Clair gets =  [tex]\frac{9}{16}[/tex]·x = [tex]\frac{9}{16}[/tex] × R2000 = R1,125

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