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Which equation can be used to find the measure of
angle BAC?
tan-1_5
-X
12
1
= x
O ) =
O tan-( 13 ) =>
O cos-1( 13 ) = x
-1 ( 132 ) = x
12
=
O cos-1


Sagot :

Answer:

our answer will be in quadrant 1 only.

Step-by-step explanation:

From the

cos−1(1) we have the side adjacent to ∠θ=1 and the side hypotenuse=2 . So this is a 30∘−60∘−90∘ triangle and θ=60∘therefore the opposite to ∠θ=√3.

Note that from the restrictions for the range of inverse circular functions cos−1x is restricted to quadrants 1 and 2 and since the argument is positive 12 our answer will be in quadrant 1 only.

The equation that can be used to find the measure of angle BAC is [tex]A = \tan^{-1}(\frac{12}5)[/tex]

To find the measure of angle BAC, we make use of the following tangent ratio

[tex]\tan(A) = \frac{12}5[/tex]

Next, we take the arc tan of both sides

[tex]\tan^{-1}(\tan(A)) = \tan^{-1}(\frac{12}5)[/tex]

So, we have:

[tex]A = \tan^{-1}(\frac{12}5)[/tex]

Hence, the equation that can be used to find the measure of angle BAC is [tex]A = \tan^{-1}(\frac{12}5)[/tex]

Read more about tangent ratios at:

https://brainly.com/question/14169279