Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

The length of the base of the triangle is 6x -2 meters, the height of the triangle is (3x+2)². find the algebraic expression of the area of the triangle (area=bxh/2)

Sagot :

Answer:

  • 27x³ + 27x² - 4 meters²

Explanation:

To find the area of the triangle, we must multiply 1/2 x base x altitude to get the answer. But first, we need to simplify the height. We are given the base and the altitude.

  • Base = 6x - 2
  • Height = (3x + 2)²

Solution:

  • Area of triangle = 1/2 x (6x - 2) x (3x + 2)²
  • => Area of triangle = 1/2 x (6x - 2) x (3x + 2)(3x + 2)
  • => Area of triangle = 1/2 x (6x - 2) x (3x + 2)(3x + 2)
  • => Area of triangle = 1/2 x (6x - 2) x (9x² + 6x + 6x + 4)
  • => Area of triangle = 1/2 x (6x - 2) x (9x² + 12x + 4)
  • => Area of triangle = 1/2 x (54x³ - 18x² + 72x² - 24x + 24x - 8)
  • => Area of triangle = 1/2 x (54x³ + 54x² - 8)
  • => Area of triangle = (54x³/2 + 54x²/2 - 8/2)
  • => Area of triangle = 27x³ + 27x² - 4 meters²

Hence, the area of the triangle is 27x³ + 27x² - 4 meters².