Answered

Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Consider the reaction 2SO2(g) O2(g) Right arrow. 2SO3(g). Substance Delta. Hf (kJ/mol) S (J/(molmc021-3. JpgK)) SO3(g) –396 130. 58 SO2(g) –297 191. 50 O2(g) 0 205. 00 What is the Delta. Grxn of this reaction, and would it be spontaneous or nonspontaneous at 300. 0 K? Use Delta. G = Delta. H – TDelta. S. –296 kJ/mol, spontaneous –296 kJ/mol, nonspontaneous –100 kJ/mol, spontaneous –100 kJ/mol, nonspontaneous.

Sagot :

The reaction has [tex]\Delta G[/tex] value of -296 kJ/mol, and the reaction is spontaneous. Hence, option A is correct.

The value of [tex]\Delta G[/tex] for the reaction is the change in the free energy. The [tex]\Delta G[/tex] for the reaction is calculated as:

[tex]\Delta G=\Delta H-T\Delta S[/tex]

Computation for [tex]\Delta G[/tex] of the reaction

The given reaction is:
[tex]\rm 2\;SO_2\;+\;O_2\;\to\;2\;SO_3[/tex]

The change in enthalpy and entropy is given by the difference in product and reactant.

Thus, the change in free energy is given as:

[tex]\Delta G=(\Delta H_{product}-\Delta H_{reactant})-T(\Delta S_{product}-\Delta S_{reactant})\\\\\Delta G=(2(\Delta H_{SO_3})-(2(\Delta H_{SO_2})\;+\;\Delta S_{O_2}))-T((2(\Delta S_{SO_3})-(2(\Delta S_{SO_2}))[/tex]

Substituting the values in the above equation at a temperature of 300 K.

[tex]\Delta G=(2(-396)-(2(-297)\;+\;(0)))-300\;(2(130.58)-(2(191.50)+(205)))\\\Delta G=(-792-(-1386))-300\;(261.16+588)\\\Delta G=-296\; \rm kJ/mol[/tex]

The negative value of [tex]\Delta G[/tex] represents the reaction to be spontaneous.

Thus, the reaction has [tex]\Delta G[/tex] value of -296 kJ/mol, and the reaction is spontaneous. Hence, option A is correct.

Learn more about free energy, here:

https://brainly.com/question/14143095

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.