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Sagot :
The magnitude of the electric field inside the picture tube is 998.476 kN/C.
What is an electric field?
It is an area in the space where a charged particle experiences a force. It can be calculated by the formula,
[tex]E =\dfrac {kQ}{r^2 }[/tex]
Where,
[tex]E[/tex] = electric field produced
[tex]Q[/tex] = charge = [tex]1.602 \times 10^{-19}\rm \ C[/tex]
[tex]r[/tex] = distance = [tex]38 \times 10^{-9}\rm \ m[/tex]
[tex]k[/tex] = Coulomb's constant = [tex]9 \times 10^9 \rm \ N. m2 / C2[/tex]
Put the values in the formula,
[tex]E = \dfrac {9 \times 10^9\times 1.602 \times 10^{-19}}{(38 \times 10^{-9})^2}\\\\E = 998.476 \rm \ kN/C[/tex]
Therefore, the magnitude of the electric field inside the picture tube is 998.476 kN/C.
Learn more about the electric field:
https://brainly.com/question/3783640
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