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Sagot :
She will use (D). Multiply wavelength and frequency to calculated the speed of the wave.
Introduction
Hi ! Here, I will help explain to you about the speed of propagation of electromagnetic waves. Generally, in a vacuum, the speed of electromagnetic waves will always be the same (forming a constant) whose value is almost close to [tex] \sf{3 \times 10^8} [/tex] m/s. Each type of electromagnetic wave has its own wavelength, as well as the frequency. This means, the larger the wavelength, the smaller the frequency.
Explanation
For more details, below is the formula for the relationship between the constant of the speed of light with the wavelength and frequency :
[tex] \boxed{\sf{\bold{c = \lambda \times f}}} [/tex]
With the following condition :
- c = the constant of the speed of light in a vacuum ≈ [tex] \sf{3 \times 10^{8} \: m/s} [/tex]
- [tex] \sf{\lambda} [/tex] = wavelength (m)
- f = electromagnetic wave frequency (Hz)
Conclusion :
She will use (D). Multiply wavelength and frequency to calculated the speed of the wave.
See More :
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- What is the foton energy https://brainly.com/question/26518899
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