Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

What are the solutions to the quadratic equation below?
X^2 +13x + 40 =0
A. X = -10 and x = 4
B. X= 10 and X = 4
C. X = 8 and x = -5
o
D. X = -8 and x = -5

Sagot :

tajudeenoseni

Using factorization method;

x²+13x+40=0

x²+13+40

Find two numbers that you can add together to give the co-efficient of variable x. (I.e 13 for this question). Also, you'll find two numbers that you can multiply with each other to give you the whole number as an answer. (I.e 40 in this question). The two numbers must be the same (i.e the two numbers that will be added to give the co-efficient of x and the two numbers that will be multiplied to give the whole number must be the same two).

The two numbers are +5 and +8

The equation will therefore be = x²+5x+8x+40

You'll then factorize (I.e use a common factor of both values to bracket them)

x(x+5)+8(x+5)

(x+8)(x+5)

x is therefore (x+8=0) or (x+5=0)

x=(x=0-8) or (x=0-5)

x= -8 or x= -5

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.