Answered

Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

For the process 2SO2(g) O2(g) Right arrow. 2SO3(g), Delta. S = –187. 9 J/K and Delta. H = –198. 4 kJ at 297. 0 K are known. What is the entropy of this reaction? Use Delta. G = Delta. H – TDelta. S. –386. 3 J/K –198. 4 kJ/K –187. 9 J/K –139. 3 kJ.

Sagot :

[tex]\rm -187.9 \;J/K[/tex]entropy of the reaction.

Entropy is the amount of heat or temperature inaccessible for the system to work and convert the chemical or thermal energy into mechanical energy.

How to calculate the entropy?

Given,

  • [tex]\rm \Delta S[/tex] = [tex]\rm -187.9 \;J/K[/tex]
  • [tex]\rm \Delta H[/tex] = -198.4 kJ
  • Temperature (T) = 297.0 K

The balanced reaction can be shown as,

[tex]\rm 2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)[/tex]

The Gibbs free energy can be calculated as:

[tex]\rm \Delta G = \Delta H - \rm T\Delta S[/tex]

Here,[tex]\rm \Delta G[/tex] = gibbs free energy, [tex]\rm \Delta H[/tex] = change in enthalpy, T = temperature and [tex]\rm \Delta S[/tex] = change in entropy.

Substituting values in the equation:

[tex]\begin{aligned}\rm \Delta G &= -198400 \;\rm kJ -297 \times (-187.9\;\rm kJ/mol)\\\\\rm \Delta G &= -198400 + 55806.3\\\\\rm \Delta G &= - 142593.7 \;\rm kJ\end{aligned}[/tex]

Therefore, [tex]\rm -187.9 \;J/K[/tex] is the entropy [tex](\rm \Delta S)[/tex] of the reaction.

Learn more about entropy here:

https://brainly.com/question/4617981

Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.