The ranking of stores from the cheapest to the most expensive sale price of the camera will be D, C, B, A. The sale price of the camera will be calculated after deducting the discount from the price.
Discount can be defined as a reduction in the price of a good normally given to attract customers and increase sales. Discounts are generally calculated as a percentage of the price of the product.
The sale price of the camera in each store after discount can be calculated as follows:
[tex]\rm Sale\: price = Original\:price - Discount[/tex]
Store A:
[tex]\begin{aligned} \rm Sale\: price &= Original\:price - Discount\\\\&= \$99.99 - 15\% \:of\: \$99.99\\\\&= \$99.99 - (\$99.99 \times \dfrac{15}{100})\\\\&= \$99.99 - \$14.9985\\\\&= \$84.9915 \end[/tex]
Store B:
[tex]\begin{aligned} \rm Sale\: price &= Original\:price - Discount\\\\&= \$95.99 - 12\% \:of\: \$95.99\\\\&= \$95.99 - (\$95.99 \times \dfrac{12}{100})\\\\&= \$95.99 - \$11.5188\\\\&= \$84.4712 \end[/tex]
Store C:
[tex]\begin{aligned} \rm Sale\: price &= Original\:price - Discount\\\\&= \$90.99 - 10\% \:of\: \$90.99\\\\&= \$90.99 - (\$90.99 \times \dfrac{10}{100})\\\\&= \$90.99 - \$9.099\\\\&= \$81.891 \end[/tex]
Store D:
Since store D is giving successive discounts of 5% over the discount of 5%, the price will be:
[tex]\begin{aligned} \rm Sale \:price &= \$89.99 - 5\% \:of\:\$89.99 - 5\%\: of (\$89.99 - 5\% \:of\:\$89.99)\\\\&= \$89.00 - (\$89.99 \times \dfrac{5}{100}) - [(\$89.00 - (\$89.99 \times \dfrac{5}{100}))\dfrac{5}{100}]\\\\&= \$89.00 - \$4.4995 - [(\$89.00 - \$4.4995)\dfrac{5}{100}]\\\\&= \$85.4905 - \$4.274525\\\\&= \$81.22\end[/tex]
Therefore the ranking will be D, C, B, and A
Hence the correct option is D.
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