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Sagot :
The temperature of Boiling Water in °c is;
T₁ = 121.22 °c
Use of Clausius Clapeyron Equation
We are given;
Initial atmospheric Pressure; P₁ = 375 torr
∆h(vap) of water= 40. 7 kj/mol = 40700 J/mol
Final atmospheric pressure; P₂ = 760 torr
R = 8.314 10⁻³ kj/mol.k = 8.314 j/mol.k
Using Clausius Clapeyron Equation, we have;
In(P₂/P₁) = (-∆h/R) * (1/T₂ - 1/T₁)
where T₂ = 373.15 K (boiling point)
Thus;
In(760/375) = -(40700/8.314) * (1/373.15 - 1/T₁)
0.70639 = -4895.357 * (0.00268 - 1/T₁)
(0.00268 - 1/T₁) = -0.70639/4895.357
0.0268 - 1/T₁ = -0.0001443
1/T₁ = 0.00268 - 0.0001443
T₁ = 1/0.0025357
T₁ = 394.37 K
in °c gives; T₁ = 121.22 °c
Read more about the use of Clausius-Clapeyron Equation at; https://brainly.com/question/21504082
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