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1,write the successor of-5 and predecessor of 6 then add them
2,find the value of a-b if a and b are two integers such that a is the predecessor of b
3,subtract the sum of 100and -24 from the sum of 42 and -66​

Sagot :

#1

  • Successor of -5=-4
  • Predecessor of 6=5

[tex]\\ \tt\hookrightarrow -4+5=1[/tex]

#2

  • Let one be x and other be x-1

[tex]\\ \tt\hookrightarrow a-b=x-x+1=+1[/tex]

#3

[tex]\\ \tt\hookrightarrow 42-66-(100-24)[/tex]

[tex]\\ \tt\hookrightarrow -24-76[/tex]

[tex]\\ \tt\hookrightarrow -100[/tex]

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Step by Step Solution for Part-1:

We know that:

  • The successor of a number defines one to be added to a number
  • The predecessor of a number defines one being subtracted to a number

Solution:

  • ⇒ (-5 + 1) + (6 - 1)
  • ⇒ (-4) + (5)
  • ⇒ 1

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Step by Step Solution for Part-2:

We know that:

  • b - 1 = a
  • To solve: a - b

Solution:

  • ⇒ a - b
  • ⇒ (b - 1) - b
  • ⇒ (-b + 1) + b
  • ⇒ -b + 1 + b
  • ⇒ 1

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Step by Step Solution for Part-3:

  • (42 - 66) - (100 - 24)
  • => (-24) - (76)
  • => -100

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