kendallsbackup435
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help please!
What is the area of this trapezoid?


108 in²

139.5 in²

166 in²

171 in²

Help Please What Is The Area Of This Trapezoid 108 In 1395 In 166 In 171 In class=

Sagot :

(2x9)/2 =9
(5x9)/2 =22.5
12x9 =108
108+22.5+9=
139.5 in^2

Answer:

A = 139.5 in²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = [tex]\frac{1}{2}[/tex] h (b₁ + b₂)

where h is the perpendicular height between the bases b₁ and b₂

here h = 9 , b₁ = 12 and b₂ = 2 + 12 + 5 = 19 , then

A = [tex]\frac{1}{2}[/tex] × 9 × (12 + 19) = 4.5 × 31 = 139.5 in²

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