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Sagot :
0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.
Total atoms in a compound
Given the following parameters
- Mass of Cu2s = 32.8 grams
Get the number of moles
- Moles = Mass/Molar mass
Moles = 32.8/159.16 g/mol
Moles of Cu2S = 0.240moles
Since 1 molecule of atom = 6.02 * 10^23 molecules
Hence 0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.
Learn more on molecules of compound here: https://brainly.com/question/473667
The number of atoms that are present in 32.8 grams of Cu2S is; 1.235 × 10²³ atoms
Number of atoms and Avogadro's number
The molar mass of Cu2S is; 64 +64 + 32
Hence, molar mass = 160.
Hence, the no. if moles in 32.8 grams of Cu2S is;
- No. of moles, n = 32.8/160
- n = 0.205.
Hence, the no. of atoms in the given sample is;
- No. of atoms = n × Avogadro's number
- No of atoms = 0.205 × 6.022 × 10²³
No. of atoms = 1.235 × 10²³ atoms
Read more on Avogadro's number;
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