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How many total atoms are present in 32. 8 grams of cu2s?.

Sagot :

abidemiokin

0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.

Total atoms in a compound

Given the following parameters

  • Mass of  Cu2s = 32.8 grams

Get the number of moles

  • Moles = Mass/Molar mass

Moles = 32.8/159.16 g/mol

Moles of Cu2S = 0.240moles

Since 1 molecule of atom  = 6.02 * 10^23 molecules

Hence 0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.

Learn more on molecules of compound here: https://brainly.com/question/473667

adioabiola

The number of atoms that are present in 32.8 grams of Cu2S is; 1.235 × 10²³ atoms

Number of atoms and Avogadro's number

The molar mass of Cu2S is; 64 +64 + 32

Hence, molar mass = 160.

Hence, the no. if moles in 32.8 grams of Cu2S is;

  • No. of moles, n = 32.8/160

  • n = 0.205.

Hence, the no. of atoms in the given sample is;

  • No. of atoms = n × Avogadro's number

  • No of atoms = 0.205 × 6.022 × 10²³

No. of atoms = 1.235 × 10²³ atoms

Read more on Avogadro's number;

https://brainly.com/question/1528951

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