Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.
Total atoms in a compound
Given the following parameters
- Mass of Cu2s = 32.8 grams
Get the number of moles
- Moles = Mass/Molar mass
Moles = 32.8/159.16 g/mol
Moles of Cu2S = 0.240moles
Since 1 molecule of atom = 6.02 * 10^23 molecules
Hence 0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.
Learn more on molecules of compound here: https://brainly.com/question/473667
The number of atoms that are present in 32.8 grams of Cu2S is; 1.235 × 10²³ atoms
Number of atoms and Avogadro's number
The molar mass of Cu2S is; 64 +64 + 32
Hence, molar mass = 160.
Hence, the no. if moles in 32.8 grams of Cu2S is;
- No. of moles, n = 32.8/160
- n = 0.205.
Hence, the no. of atoms in the given sample is;
- No. of atoms = n × Avogadro's number
- No of atoms = 0.205 × 6.022 × 10²³
No. of atoms = 1.235 × 10²³ atoms
Read more on Avogadro's number;
https://brainly.com/question/1528951
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.