Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Get expert answers to your questions quickly and accurately from our dedicated community of professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

How many total atoms are present in 32. 8 grams of cu2s?.

Sagot :

0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.

Total atoms in a compound

Given the following parameters

  • Mass of  Cu2s = 32.8 grams

Get the number of moles

  • Moles = Mass/Molar mass

Moles = 32.8/159.16 g/mol

Moles of Cu2S = 0.240moles

Since 1 molecule of atom  = 6.02 * 10^23 molecules

Hence 0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.

Learn more on molecules of compound here: https://brainly.com/question/473667

The number of atoms that are present in 32.8 grams of Cu2S is; 1.235 × 10²³ atoms

Number of atoms and Avogadro's number

The molar mass of Cu2S is; 64 +64 + 32

Hence, molar mass = 160.

Hence, the no. if moles in 32.8 grams of Cu2S is;

  • No. of moles, n = 32.8/160

  • n = 0.205.

Hence, the no. of atoms in the given sample is;

  • No. of atoms = n × Avogadro's number

  • No of atoms = 0.205 × 6.022 × 10²³

No. of atoms = 1.235 × 10²³ atoms

Read more on Avogadro's number;

https://brainly.com/question/1528951