At Westonci.ca, we connect you with experts who provide detailed answers to your most pressing questions. Start exploring now! Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.
Total atoms in a compound
Given the following parameters
- Mass of Cu2s = 32.8 grams
Get the number of moles
- Moles = Mass/Molar mass
Moles = 32.8/159.16 g/mol
Moles of Cu2S = 0.240moles
Since 1 molecule of atom = 6.02 * 10^23 molecules
Hence 0.206 moles will contain 0.206 moles x 6.022 × 10^23 atoms which is equivalent to 1.240 x 10^23 atoms.
Learn more on molecules of compound here: https://brainly.com/question/473667
The number of atoms that are present in 32.8 grams of Cu2S is; 1.235 × 10²³ atoms
Number of atoms and Avogadro's number
The molar mass of Cu2S is; 64 +64 + 32
Hence, molar mass = 160.
Hence, the no. if moles in 32.8 grams of Cu2S is;
- No. of moles, n = 32.8/160
- n = 0.205.
Hence, the no. of atoms in the given sample is;
- No. of atoms = n × Avogadro's number
- No of atoms = 0.205 × 6.022 × 10²³
No. of atoms = 1.235 × 10²³ atoms
Read more on Avogadro's number;
https://brainly.com/question/1528951
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.