Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Discover in-depth answers to your questions from a wide network of experts on our user-friendly Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

in a sealed and rigid container, a sample of gas at 2.00 atm and 25.0 °c is heated to 50.0 °c. what is the pressure (in atm) of the gas at 50.0 °c?

Sagot :

okpalawalter8

We have that the  the pressure (in atm) of the gas at 50.0 °c is mathematically given as

P2= 2.17 atm

Gay-Lussac's law

The Gay-Lussac's law states that pressure exerted by gas is directly proportional to the absolute temperature of the gas.

Generally the equation for the Gay-Lussac's law  is mathematically given a

P1 / T1 = P2 / T2

Therefore

T1 = 25C

T1= 25 + 273

T1= 298 K

And

T2 = 50C

T2= 50 + 273

T2= 323 K

Therefore

[tex]P2 = \frac{2.00 x 323}{298 }[/tex]

P2= 2.17 atm

Hence,  the pressure (in atm) of the gas at 50.0 °c is

[tex]P2 = \frac{2.00 x 323}{298 }[/tex]

P2= 2.17 atm

For more information on Temperature visit

https://brainly.com/question/15267055

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.