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A lunar lander is making its descent to moon base i (figure 1). The lander descends slowly under the retro-thrust of its descent engine. The engine is cut off when the lander is 5. 0 m above the surface and has a downward speed of 0. 80 m/s. With the engine off, the lander is in free fall.

Sagot :

annyksl

The speed before landing on the surface will be equal to 1.1 m/s

Calculate to get the result:

  • To achieve this result, we will only need to follow a single formula which is:

[tex]V_f=\sqrt{(V_i)^2+2*a*d}[/tex]

  • With this, we can calculate as follows:

[tex]V_f=\sqrt{(0.8)^2+2*1.6*5} \\V_f= 1.1 m/s[/tex]

The above question is incomplete. The complete question is in the figure below.

More information about speed in the link below:

https://brainly.com/question/4931057

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